Solving adfected quadratic equations (Part 3)

Solving adfected quadratic equations (Part 3)

Lesson details

Key learning points

  1. In this lesson, we will solve quadratic equations that first need to be rearranged.

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5 Questions

Q1.
Find the solutions to 'A'
y = - 5 and y = -2
Correct answer: y = -7 and y = -3
y = 5 and y = 2
y=7 and y = 3
Q2.
Find the solutions to 'B'
Correct answer: y = - 5 and y = -10
y = -5 and y = -3
y = 5 and y = 10
y= 5 and y = 3
Q3.
Find the solutions to 'C'
Correct answer: y = 0 and y = -10
y = 0 and y = 10
y = 1 and y = 10
y= 1 and y = -10
Q4.
Find the solutions to 'D'
y = 0 and y = -100
y = 10
Correct answer: y = 10 and y =- 10
Q5.
Find the solutions to 'E'
y = 81
y = 9
Correct answer: y = 9 and y = -9

5 Questions

Q1.
A quadratic equation must have two solutions. True or false?
Correct answer: False
True
Q2.
what are the solutions to the quadratic equation in question a?
x = -3 or x = -15
x = -5 or x = -9
Correct answer: x = 5 or x = 9
x= - 15 and x = -3
Q3.
what are the solutions to the quadratic equation in question b?
x = -14 or x = -3
x = 14 or x = 3
x = 6 or x = 7
Correct answer: x= -6 and x = -7
Q4.
what are the solutions to the quadratic equation in question c?
x = -3 or x = 7
x = -4 or x = 4
Correct answer: x = 4 or x = -8
x= 3 and x = -7
Q5.
what are the solutions to the quadratic equation in question d?
x = -1 or x = 7
x = 0 or x = -6
x = 0 or x = 6
Correct answer: x= 1 and x = -7

Lesson appears in

UnitMaths / Quadratic equations (9.10)