Circle Theorems: The perpendicular from the centre to a chord bisects the chord

Circle Theorems: The perpendicular from the centre to a chord bisects the chord

Lesson details

Key learning points

  1. In this lesson, we will learn that a perpendicular from the centre to a chord bisects the chord. We will prove this result with a general case.

Licence

This content is made available by Oak National Academy Limited and its partners and licensed under Oak’s terms & conditions (Collection 1), except where otherwise stated.

Loading...

3 Questions

Q1.
Work out the missing angle x.
108º
48º
Correct answer: 60º
72º
Q2.
Work out the missing angle y.
108º
Correct answer: 48º
60º
72º
Q3.
Work out the missing angle x.
Correct answer: 104º
118º
42º
62º

3 Questions

Q1.
Work out the length of the AM.
Correct answer: 11 cm
33 cm
44 cm
5.5 cm
Q2.
Work out the length of BM.
Correct answer: 12 cm
18 cm
24 cm
6 cm
Q3.
The diagram shows a circle with centre O and M is the midpoint of chord AB. Which statement is INCORRECT?
AM=0.5AB
AM=BM
Correct answer: OA=AM
OA=OB

Lesson appears in

UnitMaths / Circle Theorems 2